Cogito wrote:
An easy way to look at it:
Suppose speaker impedance is 8ohms and voltage of the signal is 20V.
For single speaker:
Using Ohms Law, Current: I = V/R = 20V/8Ohms = 2.5 W
Power = VI = 20 * 2.5 = 50W
For two speakers connected in serial:
Using Ohms Law, Current: I = V/R = 20V/16Ohms = 1.25 W
Power = VI = 20 * 1.25 = 25W
For two speakers connected in Parallel:
Current = 20V/4Ohms = 5W
Power = VI = 20 * 5 = 100W
So, a low power tube amp which can drive 8 ohms speakers nicely might struggle driving a 4 ohm speaker or two 8 ohm speakers connected in parallel.
Actually, since the power sensitivity went up by 3dB, it ought to be EASIER for the amp to drive the 4ohm load created by two 8ohm speakers in parallel, assuming the OPT has a 4ohm tap. You're only looking at 20V across all three scenarios if you don't change output taps or use an amp (SS probably) with a vanishingly low output impedance. Remember, if you use the 16ohm tap to drive the series connection, and the 4ohm tap to drive the parallel connection, you're only getting half the voltage at the amp output for the same power delivered to the speakers.
BTW, it would be a lot simpler to follow if you just used V^2/R for power

Roscoe